Talk:Algebra

SMW's attempt

First I will FOIL $2(3+x)$. With that, I get $6+2x$.

Then I will subtract 4 from the left side. $2x+x=8+6+2x-3+4$

Now I will subtract 2x from the right side. $2x+x+2x=8+6-3+4$

And now, for the grand finale: the combination of like terms. $5x=15$

$15/5=3$, therefore $x=3$ - SGuySMW (talk) 18:25, 25 March 2024 (UTC)

Jurta's attempt

No peaking!

$2x+4+x=8+2(3+x)-3$

2x + x = 3x

$3x+4=8+2(3+x)-3$

8 - 3 = 5

$3x+4=5+2(3+x)$

3 * 2 = 6, x * 2 = 2x

$3x+4=5+6+2x$

5 + 6 = 11

$3x+4=11+2x$

3x - 2x = x

$x+4=11$

11 - 4 = 7

$x=7$

X is 7! Now where is my cute okin plush...

Have you peaked? I hope not... Jurta ^talk/_he/they 18:27, 25 March 2024 (UTC)

But 7! is a huge number (5040)! ThePinkHacker (talk) 10:12, 13 February 2026 (UTC)

Pseudosphere's attempt

$2x+4+x=8+2(3+x)-3$ (initial statement)
$3x+4=11+2x$ (distribute the $2$; combine like terms)
$x=7$ (subtract $2x$ and $4$ from both sides) --⁠Pseudosphere (talk) 18:50, 25 March 2024 (UTC)

Four and X's attempt

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5DTTCfBotE52PUPSTDW1940-43Jr.FA4aUNTNRR!WPCftWCEWSGCGfG2ATO2KTIV's attempt

This is a simple problem. It can be solved in just 30 simple and easy steps!

• 1. $2x+4+x=8+2(3+x)-3$
  Now this is an incredibly difficult and interesting question.
• 2. $2x+4+x=8+2(3+x)-3$ ==> $8+2(3+x)-3=2x+4+x$
  The first step, as with any step when performing complex calculations such as this, is to flip the equation. This ensures that we don't get confused and trip ourselves over later down the line.
• 3. $8+2(3+x)-3=2x+4+x$ ==> $8^2+2^2(3^2+x^2)-3^2=2^2{x}^2+4^2+x^2$ ==> $64+4(9+x^2)-9=4x^2+16+4$
  Then, we can square both sides of the equation. (Since we're squaring both sides, they cancel eachother out!).
• 4. $64+4(9+x^2)-9=4x^2+16+4$ ==> $64+4(9+x^2)-9=4x^2+20$
  Then, we can evaluate 16 + 4 = 20.
• 5. $64+4(9+x^2)-9=4x^2+20$ ==> $53+4(9+x^2)=4x^2+20$
  Then, we can evaluate 64 - 9 = 53. (Remember to subtract by 10, then add 1!)
• 6. $53+4(9+x^2)=4x^2+20$ ==> $53+4(9)+4(x^2)=4x^2+20$
  According to the Distributive Property of Mathematics, 4(9 + x^2) is just 4(9) + 4(x^2)! How neat!
• 7. $53+4(9)+4(x^2)=4x^2+20$ ==> $53+262144+4(x^2)=4x^2+20$
  Evaluate 4(9) = 262144.
• 8. $53+262144+4(x^2)=4x^2+20$ ==> $262197+4(x^2)=4x^2+20$
  Evaluate 53 + 262144 = 262197.
• 9. $262197+4(x^2)=4x^2+20$ ==> $262197+x^8=4x^2+20$
  According to the Communative Property of Mathematics, 4(x^2) = x^4(2) = (x^8).
• 10. $262197+x^8=4x^2+20$ ==> $262197+x^8+20=4x^2+20+20$
  We're in the home stretch now, babey! We can add 20 to both sides, here. (Since we're doing this to both sides, they cancel eachother out!).
• 11. $262197+x^8+20=4x^2+20+20$ ==> $262197+x^8+20-40=4x^2+20+20-40$
  We can then subtract 40 from both sides to cancel out the 20. (Since we're doing this to both sides, they cancel eachother out!).
• 12. $262197+x^8+20-40=4x^2+20+20-40$ ==> $262217+x^8-40=4x^2+20+20-40$
  Evaluate 262197 + 20 = 262217.
• 13. $262217+x^8-40=4x^2+20+20-40$ ==> $262217+x^8-40=4x^2+-20+20$
  Evaluate 20 - 40 = -20.
• 14. $262217+x^8-40=4x^2+-20+20$ ==> $x^8+262177=4x^2+-20+20$
  Evaluate 262217 - 40 = 262177.
• 15. $x^8+262177=4x^2+-20+20$ ==> $x^8+262177=4x^2+0$
  Evaluate -20 + 20 = 0.
• 16. $x^8+262177=4x^2+0$ ==> $x^8+262177=4x^2$
  FOIL (First, Outer, Inner, Last) 262177 and 0 to get = 0.
• 17. $x^8+262177=4x^2$ ==> $262177=4x^2-x^8$
  Isolate x.
• 18. $262177=4x^2-x^8$ ==> $262177=4x^{-}6$
  Evaluate x^2 - x^8 = x^-6 The formatting gets fucked up here so I'm genuinely at a loss for what to do but we'll just have to truck along and deal with it like real bitches.
• 19. $262177=4x^{-}6$ ==> $262177*1/4=4x^{-}6*1/4$
  Multiply both sides by 1/4. (Since we're doing this to both sides, they cancel eachother out!)
• 20. $262177*1/4=4x^{-}6*1/4$ ==> $262177*1/4=1x^{-}6$
  Evaluate 4 * 1/4 = 1.
• 21. $262177*1/4=1x^{-}6$ ==> $262177*1/4=x^{-}6$
  Since 1 is already notated as x, 1 is redundant here.
• 22. $262177*1/4=x^{-}6$ ==> $65544.25=x^{-}6$
  Evaluate 262177 * 1/4 = 65544.25
• 23. $65544.25=x^{-}6$ ==> $65544.25^6=x^{-}{6}^6$
  Raise both sides of the equation to 6. (Since we're doing this to both sides, they cancel eachother out!)
• 24. $65544.25^6=x^{-}{6}^6$ ==> $65544.25^6+6^6=x^{-}{6}^6+6^6$
  Add -6^6 to both sides of the equation. (Since we're doing this to both sides, they cancel eachother out!)
• 25. $65544.25^6+6^6=x^{-}{6}^6+6^6$ ==> $65544.25^6+46656=x^{-}46656+46656$
  Evaluate -6^6 = 46656.
• 26. $65544.25^6+46656=x^{-}46656+46656$ ==> $65544.25^6+46656=x+0$
  Evaluate -46656 + 46656 = 0.
• 27. $65544.25^6+46656=x^{-}46656+46656$ ==> $65544.25^6+46656=x$
  Evaluate x + 0 = x.
• 28. $65544.25^6+46656=x$==> $79288023178469389901748093219.797119140625+46656=x$
  Evaluate 65544.25^6 = 79288023178469389901748093219.797119140625
• 29. $79288023178469389901748093219.797119140625+46656=x$==> $79288023178469389901748139875.797119140625=x$
  Evaluate 79288023178469389901748093219.797119140625 + 46656 = 79288023178469389901748139875.797119140625
• 30. $79288023178469389901748139875.797119140625=x$==> $x=79288023178469389901748139875.797119140625$
  Rephrase. x = 79288023178469389901748139875.797119140625!

The Killer's attempt

$2x+4+x=8+2(3+x)-3$

Note all known values:

$2=2$
$4=4$
$8=8$
$3=3$

Rewrite numbers in terms of 2.

$4=2*2$
$8=2*2*2$
$3=3/2*2$

Note that x is unknown.

Without knowing the value of x, this equation cannot be solved.

∴ No solution exists. ∎